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Popular >

integral from 1 to 4 of x^2-4x-3

Solution

\int_{1}^{4} x^{2} - 4 x - 3 d x

Solution

- 18

Solution steps

\int_{1}^{4} x^{2} - 4 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x - \int_{1}^{4} 4 x d x - \int_{1}^{4} 3 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 4 x d x = 30

\int_{1}^{4} 3 d x = 9

= 21 - 30 - 9

Simplify

= - 18

Graph

Popular Examples

integral from-infinity to 4 of xe^x

\int_{- \infty}^{4} x e^{x} d x

inverse oflaplace 3/(s^2+3s+6)inverse laplace

\frac{3}{s ^{2} + 3 s + 6}

derivative of (2x^4)/(b^2-x^2)derivative of

\frac{2 x ^{4}}{b ^{2} - x ^{2}}

integral of ((x^2-x+24))/(x^3+6x)

\int \frac{( x ^{2} - x + 24 )}{x ^{3} + 6 x} d x

y=(\sqrt[5]{t})^t

y = (5 t)^{t}

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of x^2-4x-3 ?
The integral from 1 to 4 of x^2-4x-3 is -18