What is the derivative of (-3cos(2x-sin(3x)-4)^2) ?

The derivative of (-3cos(2x-sin(3x)-4)^2) is 2(-3cos(2x)-sin(3x)-4)(6sin(2x)-3cos(3x))

What is the first derivative of (-3cos(2x-sin(3x)-4)^2) ?

The first derivative of (-3cos(2x-sin(3x)-4)^2) is 2(-3cos(2x)-sin(3x)-4)(6sin(2x)-3cos(3x))

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\frac{d}{d x} ((- 3 cos (2 x) - sin (3 x) - 4)^{2})

2 (- 3 cos (2 x) - sin (3 x) - 4) (6 sin (2 x) - 3 cos (3 x))

Solution steps

\frac{d}{d x} ((- 3 cos (2 x) - sin (3 x) - 4)^{2})

Apply the chain rule:

2 (- 3 cos (2 x) - sin (3 x) - 4) \frac{d}{d x} (- 3 cos (2 x) - sin (3 x) - 4)

= 2 (- 3 cos (2 x) - sin (3 x) - 4) \frac{d}{d x} (- 3 cos (2 x) - sin (3 x) - 4)

\frac{d}{d x} (- 3 cos (2 x) - sin (3 x) - 4) = 6 sin (2 x) - 3 cos (3 x)

= 2 (- 3 cos (2 x) - sin (3 x) - 4) (6 sin (2 x) - 3 cos (3 x))

\int x^{19} I n x d x

\int \frac{5}{11 - 11 x ^{2}} d x

y^{^{'}} + 3 y = 2 t

\int sec (z) d z

\frac{d}{d x} (x e^{x - y})

What is the derivative of (-3cos(2x-sin(3x)-4)^2) ?
The derivative of (-3cos(2x-sin(3x)-4)^2) is 2(-3cos(2x)-sin(3x)-4)(6sin(2x)-3cos(3x))
What is the first derivative of (-3cos(2x-sin(3x)-4)^2) ?
The first derivative of (-3cos(2x-sin(3x)-4)^2) is 2(-3cos(2x)-sin(3x)-4)(6sin(2x)-3cos(3x))