What is the integral of 1/(x^2-3x-10) ?

The integral of 1/(x^2-3x-10) is -1/7 ln|x+2|+1/7 ln|x-5|+C

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integral of 1/(x^2-3x-10)

\int \frac{1}{x ^{2} - 3 x - 10} d x

- \frac{1}{7} ln ∣ x + 2 ∣ + \frac{1}{7} ln ∣ x - 5 ∣ + C

Solution steps

\int \frac{1}{x ^{2} - 3 x - 10} d x

Take the partial fraction of

\frac{1}{x ^{2} - 3 x - 10} : - \frac{1}{7 ( x + 2 )} + \frac{1}{7 ( x - 5 )}

= \int - \frac{1}{7 ( x + 2 )} + \frac{1}{7 ( x - 5 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{1}{7 ( x + 2 )} d x + \int \frac{1}{7 ( x - 5 )} d x

\int \frac{1}{7 ( x + 2 )} d x = \frac{1}{7} ln ∣ x + 2 ∣

\int \frac{1}{7 ( x - 5 )} d x = \frac{1}{7} ln ∣ x - 5 ∣

= - \frac{1}{7} ln ∣ x + 2 ∣ + \frac{1}{7} ln ∣ x - 5 ∣

Add a constant to the solution

= - \frac{1}{7} ln ∣ x + 2 ∣ + \frac{1}{7} ln ∣ x - 5 ∣ + C

f (x) = 7

f (x) = - 9 x

\int \frac{ln ^{8} ( x )}{x} d x

6 x^{- 4} + 5 x^{- 2}

\int ln (e^{x}) d x

What is the integral of 1/(x^2-3x-10) ?
The integral of 1/(x^2-3x-10) is -1/7 ln|x+2|+1/7 ln|x-5|+C