What is the derivative of f(x)=x^2+x-6 ?

The derivative of f(x)=x^2+x-6 is 2x+1

What is the first derivative of f(x)=x^2+x-6 ?

The first derivative of f(x)=x^2+x-6 is 2x+1

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derivative of

f (x) = x^{2} + x - 6

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (6)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

\frac{d}{d x} (5 \cdot sin (x))

\frac{d y}{d t} = t^{2} - 2

\int e^{l n (x)} x d x

f (x) = 3 x^{2} + 5 x + 1

y = \frac{1}{( x ^{2} - 3 ) ( x ^{2} + 3 x + 3 )}

What is the derivative of f(x)=x^2+x-6 ?
The derivative of f(x)=x^2+x-6 is 2x+1
What is the first derivative of f(x)=x^2+x-6 ?
The first derivative of f(x)=x^2+x-6 is 2x+1