What is the derivative of 9/(1-x) ?

The derivative of 9/(1-x) is 9/((1-x)^2)

What is the first derivative of 9/(1-x) ?

The first derivative of 9/(1-x) is 9/((1-x)^2)

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\frac{d}{d x} (\frac{9}{1 - x})

\frac{9}{( 1 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{1 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{1 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((1 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

= - \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 9 (- \frac{1}{( 1 - x ) ^{2}} (- 1))

Simplify

9 (- \frac{1}{( 1 - x ) ^{2}} (- 1)) : \frac{9}{( 1 - x ) ^{2}}

= \frac{9}{( 1 - x ) ^{2}}

x \to 5 + lim (\frac{1}{x - 5})

\int sec^{4} (x) tan (x) d x

\frac{d}{d x} (- \frac{13 e ^{\frac{1}{x}}}{x ^{2}})

x \to 14 lim (x^{2} - 9)

y = \frac{1}{x}, y = x

What is the derivative of 9/(1-x) ?
The derivative of 9/(1-x) is 9/((1-x)^2)
What is the first derivative of 9/(1-x) ?
The first derivative of 9/(1-x) is 9/((1-x)^2)