What is the integral of x/(\sqrt[4]{x+6)} ?

The integral of x/(\sqrt[4]{x+6)} is 4/7 (x+6)^{7/4}-8(x+6)^{3/4}+C

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integral of x/(\sqrt[4]{x+6)}

\int \frac{x}{4 x + 6} d x

\frac{4}{7} (x + 6)^{\frac{7}{4}} - 8 (x + 6)^{\frac{3}{4}} + C

Solution steps

\int \frac{x}{4 x + 6} d x

Apply u-substitution

: \int \frac{u - 6}{4 u} d u

= \int \frac{u - 6}{4 u} d u

Expand

\frac{u - 6}{4 u} : u^{\frac{3}{4}} - \frac{6}{4 u}

= \int u^{\frac{3}{4}} - \frac{6}{4 u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{3}{4}} d u - \int \frac{6}{4 u} d u

\int u^{\frac{3}{4}} d u = \frac{4}{7} u^{\frac{7}{4}}

\int \frac{6}{4 u} d u = 8 u^{\frac{3}{4}}

= \frac{4}{7} u^{\frac{7}{4}} - 8 u^{\frac{3}{4}}

Substitute back

u = x + 6

= \frac{4}{7} (x + 6)^{\frac{7}{4}} - 8 (x + 6)^{\frac{3}{4}}

Add a constant to the solution

= \frac{4}{7} (x + 6)^{\frac{7}{4}} - 8 (x + 6)^{\frac{3}{4}} + C

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What is the integral of x/(\sqrt[4]{x+6)} ?
The integral of x/(\sqrt[4]{x+6)} is 4/7 (x+6)^{7/4}-8(x+6)^{3/4}+C