What is the solution for x^2y^{''}+9xy^'+16y=0 ?

The solution for x^2y^{''}+9xy^'+16y=0 is y=(c_{1})/(x^4)+(c_{2}ln(x))/(x^4)

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x^2y^{''}+9xy^'+16y=0

x^{2} y^{^{''}} + 9 x y^{^{'}} + 16 y = 0

y = \frac{c _{1}}{x ^{4}} + \frac{c _{2} ln ( x )}{x ^{4}}

Solution steps

x^{2} y^{''} (x) + 9 x y^{'} (x) + 16 y = 0

Solve linear ODE:

y = \frac{c _{1}}{x ^{4}} + \frac{c _{2} ln ( x )}{x ^{4}}

y = \frac{c _{1}}{x ^{4}} + \frac{c _{2} ln ( x )}{x ^{4}}

f (x) = sin (5 x)

x \to - 3 lim (- x^{2} + 6 x - 2)

\int 54.0595 e^{x} x d x

\frac{\partial}{\partial x} (in \frac{x + y}{x - y})

\frac{d}{d x} (\frac{x ^{2}}{( x + 2 i ) ^{2}})

What is the solution for x^2y^{''}+9xy^'+16y=0 ?
The solution for x^2y^{''}+9xy^'+16y=0 is y=(c_{1})/(x^4)+(c_{2}ln(x))/(x^4)