What is the derivative of 2e^x(cos(x)-sin(x)) ?

The derivative of 2e^x(cos(x)-sin(x)) is -4e^xsin(x)

What is the first derivative of 2e^x(cos(x)-sin(x)) ?

The first derivative of 2e^x(cos(x)-sin(x)) is -4e^xsin(x)

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derivative of

2 e^{x} (cos (x) - sin (x))

- 4 e^{x} sin (x)

Solution steps

\frac{d}{d x} (2 e^{x} (cos (x) - sin (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x} (cos (x) - sin (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x) - sin (x)

= 2 (\frac{d}{d x} (e^{x}) (cos (x) - sin (x)) + \frac{d}{d x} (cos (x) - sin (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x) - sin (x)) = - sin (x) - cos (x)

= 2 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x})

Simplify

2 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x}) : - 4 e^{x} sin (x)

= - 4 e^{x} sin (x)

\int_{- 2}^{3} (x^{3} - x^{2} - 6 x) d x

\frac{d}{d t} (arcsin (t))

\frac{d}{d t} (cos (t) + sin (t))

y = x^{2} - 19, y = 18 x

y^{^{'}} + 2 y = 2 x

What is the derivative of 2e^x(cos(x)-sin(x)) ?
The derivative of 2e^x(cos(x)-sin(x)) is -4e^xsin(x)
What is the first derivative of 2e^x(cos(x)-sin(x)) ?
The first derivative of 2e^x(cos(x)-sin(x)) is -4e^xsin(x)