What is the derivative of-ln(x^2) ?

The derivative of-ln(x^2) is -2/x

What is the first derivative of-ln(x^2) ?

The first derivative of-ln(x^2) is -2/x

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\frac{d}{d x} (- ln (x^{2}))

- \frac{2}{x}

Solution steps

\frac{d}{d x} (- ln (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (x^{2}))

Apply the chain rule:

\frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

= \frac{1}{x ^{2}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - \frac{1}{x ^{2}} \cdot 2 x

Simplify

- \frac{1}{x ^{2}} \cdot 2 x : - \frac{2}{x}

= - \frac{2}{x}

\frac{d}{d x} (x^{4} - 8 x^{2} + a)

\frac{\partial}{\partial x} (e)

x \to - 19 + lim (k (x))

4 sin (π \cdot x)

What is the derivative of-ln(x^2) ?
The derivative of-ln(x^2) is -2/x
What is the first derivative of-ln(x^2) ?
The first derivative of-ln(x^2) is -2/x