What is the integral of (ln^2(x)) ?

The integral of (ln^2(x)) is xln^2(x)-2(xln(x)-x)+C

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integral of (ln^2(x))

\int (ln^{2} (x)) d x

x ln^{2} (x) - 2 (x ln (x) - x) + C

Solution steps

\int ln^{2} (x) d x

Apply Integration By Parts

: x ln^{2} (x) - \int 2 ln (x) d x

= x ln^{2} (x) - \int 2 ln (x) d x

\int 2 ln (x) d x = 2 (x ln (x) - x)

= x ln^{2} (x) - 2 (x ln (x) - x)

Add a constant to the solution

= x ln^{2} (x) - 2 (x ln (x) - x) + C

\frac{d}{d x} (cos (y) \cdot \frac{d y}{d x})

n = 2 \sum \infty \frac{1}{( n - 1 ) ^{2}}

\frac{x}{e ^{x}}

\frac{d y}{d x} = e^{5 x + 6 y}

1 + e^{2 x}

What is the integral of (ln^2(x)) ?
The integral of (ln^2(x)) is xln^2(x)-2(xln(x)-x)+C