What is the tangent of 2x^2+x ?

The tangent of 2x^2+x is y=(4a_{0}+1)x-2a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 2x^2+x

tangent of

2 x^{2} + x

y = (4 a_{0} + 1) x - 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} + a_{0})

Find the slope of

y = 2 x^{2} + x : \frac{d y}{d x} = 4 x + 1

Compute the slope of

y = 2 x^{2} + x

x = a_{0} : m = 4 a_{0} + 1

Find the line with slope m=

4 a_{0} + 1

and passing through

(a_{0}, 2 a_{0}^{2} + a_{0}) : y = (4 a_{0} + 1) x - 2 a_{0}^{2}

y = (4 a_{0} + 1) x - 2 a_{0}^{2}

\int x^{2} - \frac{1}{x ^{2}} d x

\int z d z

\frac{d}{d x} ((x + 4)^{\frac{2}{3}} (2 x^{2} - 1)^{3})

\frac{1}{( s - 1 ) ^{2} + 4}

f (x) = x^{2} + 1, at x = - 5