What is laplacetransform-4cos(5t) ?

The answer to laplacetransform-4cos(5t) is -(4s)/(s^2+25)

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laplacetransform-4cos(5t)

laplace transform

- 4 cos (5 t)

- \frac{4 s}{s ^{2} + 25}

Solution steps

L {- 4 cos (5 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 4 L {cos (5 t)}

L {cos (5 t)} : \frac{s}{s ^{2} + 25}

= - 4 \cdot \frac{s}{s ^{2} + 25}

Refine

- 4 \frac{s}{s ^{2} + 25} : - \frac{4 s}{s ^{2} + 25}

= - \frac{4 s}{s ^{2} + 25}

\int e^{y} y d y

\int_{0}^{3} x (x + 1) d x

\int 4 - 9 z^{2}

\frac{d ^{2}}{d x ^{2}} (2 e^{4 x})

(t + 1)^{3}

What is laplacetransform-4cos(5t) ?
The answer to laplacetransform-4cos(5t) is -(4s)/(s^2+25)