What is (\partial)/(\partial x)(sin(2x)cos(8y)) ?

The answer to (\partial)/(\partial x)(sin(2x)cos(8y)) is cos(8y)cos(2x)*2

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(\partial)/(\partial x)(sin(2x)cos(8y))

\frac{\partial}{\partial x} (sin (2 x) cos (8 y))

cos (8 y) cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x) cos (8 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (8 y) \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= cos (8 y) cos (2 x) \cdot 2

\frac{d ^{2}}{d x ^{2}} (x^{2} + 21)

\frac{d}{d u} (\frac{1}{u})

\int_{0}^{3} (2 x - x^{2})^{4} (1 - x) d x

\frac{d}{d x} (\frac{1}{4} (x^{2} - 4))

\frac{\partial}{\partial x} (2 x y - 18 x)

What is (\partial)/(\partial x)(sin(2x)cos(8y)) ?
The answer to (\partial)/(\partial x)(sin(2x)cos(8y)) is cos(8y)cos(2x)*2