What is the derivative of 4x^3-x ?

The derivative of 4x^3-x is 12x^2-1

What is the first derivative of 4x^3-x ?

The first derivative of 4x^3-x is 12x^2-1

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\frac{d}{d x} (4 x^{3} - x)

12 x^{2} - 1

Solution steps

\frac{d}{d x} (4 x^{3} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d x}{d x}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d x}{d x} = 1

= 12 x^{2} - 1

\frac{d}{d x} ((x^{\frac{2}{3}} + 3) (x^{\frac{1}{3}} + 5 x))

\frac{d y}{d x} = \frac{sec ( y )}{( x + 5 ) ^{2}}

\int \frac{1}{x ^{2} x ^{2} - 121} d x

\frac{d}{d x} (\frac{1 - c x}{1 + c x})

\int \frac{x ^{3}}{2 - x ^{2}} d x

What is the derivative of 4x^3-x ?
The derivative of 4x^3-x is 12x^2-1
What is the first derivative of 4x^3-x ?
The first derivative of 4x^3-x is 12x^2-1