What is the derivative of y=acsc^2(kx) ?

The derivative of y=acsc^2(kx) is -2akcsc^2(kx)cot(kx)

What is the first derivative of y=acsc^2(kx) ?

The first derivative of y=acsc^2(kx) is -2akcsc^2(kx)cot(kx)

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derivative of

y = a csc^{2} (k x)

- 2 ak csc^{2} (k x) cot (k x)

Solution steps

\frac{d}{d x} (a csc^{2} (k x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d x} (csc^{2} (k x))

Apply the chain rule:

2 csc (k x) \frac{d}{d x} (csc (k x))

= 2 csc (k x) \frac{d}{d x} (csc (k x))

\frac{d}{d x} (csc (k x)) = - cot (k x) csc (k x) k

= a \cdot 2 csc (k x) (- cot (k x) csc (k x) k)

Simplify

a \cdot 2 csc (k x) (- cot (k x) csc (k x) k) : - 2 ak csc^{2} (k x) cot (k x)

= - 2 ak csc^{2} (k x) cot (k x)

\frac{1}{( 1 + x )}

((x + 1)^{2})^{^{'}}

\int \frac{1}{x ( 64 x ^{2} - 1 ) ^{\frac{1}{2}}} d x

\frac{d}{d θ} (9 sin (θ))

What is the derivative of y=acsc^2(kx) ?
The derivative of y=acsc^2(kx) is -2akcsc^2(kx)cot(kx)
What is the first derivative of y=acsc^2(kx) ?
The first derivative of y=acsc^2(kx) is -2akcsc^2(kx)cot(kx)