What is the limit as x approaches 4+of ln(x^2-16) ?

The limit as x approaches 4+of ln(x^2-16) is -infinity

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limit as x approaches 4+of ln(x^2-16)

x \to 4 + lim (ln (x^{2} - 16))

- \infty

Solution steps

x \to 4 + lim (ln (x^{2} - 16))

Apply the Limit Chain Rule:

- \infty

= - \infty

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f (x) = 1 - x^{2}, (1, 0)

\frac{d}{d x} (\frac{( 6 x ^{2} + 6 x + 8 )}{x})

\frac{\partial}{\partial y} (x 1 + y^{3})

4 t \cdot sin (3 t)

What is the limit as x approaches 4+of ln(x^2-16) ?
The limit as x approaches 4+of ln(x^2-16) is -infinity