What is the solution for x^2y^{''}+2xy^'-2y=0 ?

The solution for x^2y^{''}+2xy^'-2y=0 is y=c_{1}x+(c_{2})/(x^2)

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x^2y^{''}+2xy^'-2y=0

x^{2} y^{^{''}} + 2 x y^{^{'}} - 2 y = 0

y = c_{1} x + \frac{c _{2}}{x ^{2}}

Solution steps

x^{2} y^{''} (x) + 2 x y^{'} (x) - 2 y = 0

Solve linear ODE:

y = c_{1} x + \frac{c _{2}}{x ^{2}}

y = c_{1} x + \frac{c _{2}}{x ^{2}}

f (x) = 9 e^{x} 12 x, at x = 0

\int (4 x + 2) (x^{2} + x - 1)^{5} d x

x \to + 7 lim (\frac{3}{x - 7})

\int (\frac{t ^{3} - 8 t + 1}{( 2 t ) ^{4}}) d t

y^{^{''}} + 36 y = sin (6 t)

What is the solution for x^2y^{''}+2xy^'-2y=0 ?
The solution for x^2y^{''}+2xy^'-2y=0 is y=c_{1}x+(c_{2})/(x^2)