What is area sin(x),cos(x),(3pi)/4 ,(7pi)/6 ?

The answer to area sin(x),cos(x),(3pi)/4 ,(7pi)/6 is (sqrt(3)+1)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area sin(x),cos(x),(3pi)/4 ,(7pi)/6

area

sin (x), cos (x), \frac{3 π}{4}, \frac{7 π}{6}

\frac{3 + 1}{2}

Decimal

1.36602 \dots

Solution steps

Apply the area formula:

\int_{\frac{3 π}{4}}^{\frac{7 π}{6}} ∣ sin (x) - cos (x) ∣ d x

Solve

\int_{\frac{3 π}{4}}^{\frac{7 π}{6}} ∣ sin (x) - cos (x) ∣ d x : \frac{3 + 1}{2}

The area is:

= \frac{3 + 1}{2}

\int r^{2} - y^{2} d y

y^{^{'}} - \frac{5}{3} y = 1 - \frac{1}{5} t

y y^{^{'}} = x - 1

\frac{d y}{d x} = 25 + y^{2}

\frac{d y}{d x} = 19 x + y - 19

What is area sin(x),cos(x),(3pi)/4 ,(7pi)/6 ?
The answer to area sin(x),cos(x),(3pi)/4 ,(7pi)/6 is (sqrt(3)+1)/2