What is the integral of e^{2+x} ?

The integral of e^{2+x} is e^{2+x}+C

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integral of e^{2+x}

\int e^{2 + x} d x

e^{2 + x} + C

Solution steps

\int e^{2 + x} d x

e^{2 + x} = e^{2} e^{x}

= \int e^{2} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{2} \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= e^{2} e^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{2} e^{x} = e^{2 + x}

= e^{2 + x}

Add a constant to the solution

= e^{2 + x} + C

\int sin (x) \cdot sin (n x) d x

(2 x - 1) d x + (5 y + 6) d y = 0

\frac{\partial}{\partial x} (x ln (\frac{x}{y}) + x y^{2})

\frac{c e ^{- a s}}{s ^{2}}

n = 2 \sum \infty e^{5 - 6 n}