What is area y=1+sqrt(x),y=((x+3))/3 ?

The answer to area y=1+sqrt(x),y=((x+3))/3 is 9/2

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area y=1+sqrt(x),y=((x+3))/3

area

y = 1 + x, y = \frac{( x + 3 )}{3}

\frac{9}{2}

Decimal

4.5

Solution steps

Apply the area formula:

\int_{0}^{9} 1 + x - \frac{1}{3} (x + 3) d x

Solve

\int_{0}^{9} 1 + x - \frac{1}{3} (x + 3) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

\int sec^{3} (9 x) d x

f (x) = (ln (x))^{3}, at x = 3

\int \frac{( 5 x + 1 )}{( 2 x + 1 ) ( x - 1 )} d x

y^{^{''''}} + 3 y^{^{''}} - 4 y = 0

arctan (\frac{x - 1}{x + 1})

What is area y=1+sqrt(x),y=((x+3))/3 ?
The answer to area y=1+sqrt(x),y=((x+3))/3 is 9/2