What is the solution for 11/4 x^2dy-14dx=0 ?

The solution for 11/4 x^2dy-14dx=0 is y=-(56)/(11x)+c_{1}

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11/4 x^2dy-14dx=0

\frac{11}{4} x^{2} d y - 14 d x = 0

y = - \frac{56}{11 x} + c_{1}

Solution steps

\frac{11}{4} x^{2} d y - 14 d x = 0

Let

y

be the dependent variable. Divide by

d x

\frac{11}{4} x^{2} \frac{d y}{d x} - 14 = 0

Substitute

\frac{d y}{d x}

with

y^{'} (x)

\frac{11}{4} x^{2} y^{^{'}} (x) - 14 = 0

Isolate

y^{'} (x) : y^{'} (x) = \frac{56}{11 x ^{2}}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{56}{11 x ^{2}} d x

\int \frac{56}{11 x ^{2}} d x = - \frac{56}{11 x} + c_{1}

y = - \frac{56}{11 x} + c_{1}

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\int \frac{6 e ^{2 x}}{3 - e ^{4 x}} d x

\frac{4}{x ^{4}}

\frac{\partial}{\partial x} ((5 x + 6 y) - (x^{2} - 4 x y + 8 y^{2} + 7 x - 14 y - 6))

\int_{- 1}^{3} 1 + 4 x^{2} d x

What is the solution for 11/4 x^2dy-14dx=0 ?
The solution for 11/4 x^2dy-14dx=0 is y=-(56)/(11x)+c_{1}