en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^'-y=x

Solution

x y^{^{'}} - y = x

Solution

y = ln (x) x + c_{1} x

Solution steps

x y^{'} (x) - y = x

Solve linear ODE:

y = ln (x) x + c_{1} x

y = ln (x) x + c_{1} x

Graph

Popular Examples

(x \cdot sin (x))^{^{'}}

(dy)/(dx)=(3y^2+2xy)/(2xy+x^2)

\frac{d y}{d x} = \frac{3 y ^{2} + 2 x y}{2 x y + x ^{2}}

derivative of 4-x^2-y^2

\frac{d}{d x} (4 - x^{2} - y^{2})

derivative of f(x)=sin(x)+1/2 cot(x)derivative of

f (x) = sin (x) + \frac{1}{2} cot (x)

integral from-2 to 0 of (2+sqrt(4-x^2))

\int_{- 2}^{0} (2 + 4 - x^{2}) d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'-y=x ?
The solution for xy^'-y=x is y=ln(x)x+c_{1}x