What is (\partial)/(\partial x)(2x^y) ?

The answer to (\partial)/(\partial x)(2x^y) is 2yx^{y-1}

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(\partial)/(\partial x)(2x^y)

\frac{\partial}{\partial x} (2 x^{y})

2 y x^{y - 1}

Solution steps

\frac{\partial}{\partial x} (2 x^{y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (x^{y})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y x^{y - 1}

\frac{d x}{d t} = x - 11

\int_{0}^{\frac{π}{2}} x sin (2 x) d x

(3, 4), (- 2, - 4)

n = 1 \sum \infty 1 3^{n} x^{n} n!

x^{3} (1.1)

What is (\partial)/(\partial x)(2x^y) ?
The answer to (\partial)/(\partial x)(2x^y) is 2yx^{y-1}