What is inverse oflaplace 1/(s+4) ?

The answer to inverse oflaplace 1/(s+4) is e^{-4t}

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inverse oflaplace 1/(s+4)

inverse laplace

\frac{1}{s + 4}

e^{- 4 t}

Solution steps

L^{- 1} {\frac{1}{s + 4}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 4}} = e^{- 4 t}

= e^{- 4 t}

\frac{d}{d x} (\frac{4}{( x + 1 ) ^{2}})

\int (\frac{2}{x} - \frac{3}{x ^{4}}) d x

y = \frac{2}{x}

\int x^{\frac{1}{2}} 1 + x^{\frac{1}{2}} d x

\int 1 0^{2 x} d x

What is inverse oflaplace 1/(s+4) ?
The answer to inverse oflaplace 1/(s+4) is e^{-4t}