What is the integral from 1 to 4 of (7x+sqrt(x)) ?

The integral from 1 to 4 of (7x+sqrt(x)) is 343/6

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integral from 1 to 4 of (7x+sqrt(x))

\int_{1}^{4} (7 x + x) d x

\frac{343}{6}

Decimal

57.16666 \dots

Solution steps

\int_{1}^{4} 7 x + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 7 x d x + \int_{1}^{4} x d x

\int_{1}^{4} 7 x d x = \frac{105}{2}

\int_{1}^{4} x d x = \frac{14}{3}

= \frac{105}{2} + \frac{14}{3}

Simplify

\frac{105}{2} + \frac{14}{3} : \frac{343}{6}

= \frac{343}{6}

\int (3 x^{2} - 4 x + 2) d x

\int \frac{2}{t} d t

n = 0 \sum \infty - n

y^{^{'}} = 3 sin (x) (2 - y)

\frac{d}{d x} (\frac{- 14}{x})

What is the integral from 1 to 4 of (7x+sqrt(x)) ?
The integral from 1 to 4 of (7x+sqrt(x)) is 343/6