What is the tangent of f(x)=(sqrt(x))/(x+1),\at x=4 ?

The tangent of f(x)=(sqrt(x))/(x+1),\at x=4 is y=-3/100 x+13/25

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tangent of f(x)=(sqrt(x))/(x+1),\at x=4

tangent of

f (x) = \frac{x}{x + 1}, at x = 4

y = - \frac{3}{100} x + \frac{13}{25}

Solution steps

Find the tangent point:

(4, \frac{2}{5})

Find the slope of

f (x) = \frac{x}{x + 1} : \frac{df ( x )}{d x} = \frac{- x + 1}{2 x ( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{100}

Find the line with slope m=

- \frac{3}{100}

and passing through

(4, \frac{2}{5}) : y = - \frac{3}{100} x + \frac{13}{25}

y = - \frac{3}{100} x + \frac{13}{25}

2 s

2 x d y + (x^{2} y^{4} + 1) y d x = 0

\int 2 cos (n x) d x

(\frac{x ^{2} + 4}{x ^{2} - 4})^{2}

\int ln (x + 7) d x

What is the tangent of f(x)=(sqrt(x))/(x+1),\at x=4 ?
The tangent of f(x)=(sqrt(x))/(x+1),\at x=4 is y=-3/100 x+13/25