What is the solution for 2xy+x^3=(xdy)/(dx) ?

The solution for 2xy+x^3=(xdy)/(dx) is y=-(x^2)/2-(2x+1)/4+c_{1}e^{2x}

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2xy+x^3=(xdy)/(dx)

2 x y + x^{3} = \frac{x d y}{d x}

y = - \frac{x ^{2}}{2} - \frac{2 x + 1}{4} + c_{1} e^{2 x}

Solution steps

2 x y + x^{3} = \frac{x d y}{d x}

Solve linear ODE:

y = - \frac{x ^{2}}{2} - \frac{2 x + 1}{4} + c_{1} e^{2 x}

y = - \frac{x ^{2}}{2} - \frac{2 x + 1}{4} + c_{1} e^{2 x}

\int \frac{sin ( 3 t + 10 )}{cos ^{2} ( 3 t + 10 )} d t

\frac{d}{d x} (2 x ln (x))

(x - y - 1)^{3} = x, (1, - 1)

y^{^{''}} + y^{^{'}} = 3 sin (4 x)

n \to \infty lim ((n!)^{n})

What is the solution for 2xy+x^3=(xdy)/(dx) ?
The solution for 2xy+x^3=(xdy)/(dx) is y=-(x^2)/2-(2x+1)/4+c_{1}e^{2x}