What is the tangent of (3x)/((x+1)^2)(0) ?

The tangent of (3x)/((x+1)^2)(0) is y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of (3x)/((x+1)^2)(0)

tangent of

\frac{3 x}{( x + 1 ) ^{2}} (0)

y = 0

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 0)

Find the slope of

y = \frac{3 x}{( x + 1 ) ^{2}} 0 : \frac{d y}{d x} = 0

Find the line with slope m=

0

and passing through

(a_{0}, 0) : y = 0

y = 0

6 x + y^{^{''}} = 0

(x^{4} - sec (4 x^{2} - 2))^{- 4}

\frac{\partial}{\partial x} (\frac{y}{x ^{2}})

\int_{0}^{10} t e^{- 0.6 t} d t

x^{^{'}} = r x - 12

What is the tangent of (3x)/((x+1)^2)(0) ?
The tangent of (3x)/((x+1)^2)(0) is y=0