What is inverse oflaplace 1/(1-s) ?

The answer to inverse oflaplace 1/(1-s) is -e^t

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inverse oflaplace 1/(1-s)

inverse laplace

\frac{1}{1 - s}

- e^{t}

Solution steps

L^{- 1} {\frac{1}{1 - s}}

= L^{- 1} {- 1 \cdot \frac{1}{s - 1}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - 1 \cdot L^{- 1} {\frac{1}{s - 1}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 1}} = e^{t}

= - 1 \cdot e^{t}

= - e^{t}

y = \frac{cos ( x )}{sin ( x )}

x \to 5 lim (\frac{x - 6}{x - 5})

\int cos (6 x) - cos (- 6 x) d x

\int \frac{cos ( θ ) - cos ( 2 θ )}{1 - cos ( θ )} d θ

x (ln (x))

What is inverse oflaplace 1/(1-s) ?
The answer to inverse oflaplace 1/(1-s) is -e^t