What is the integral from-infinity to 0 of e^{9x} ?

The integral from-infinity to 0 of e^{9x} is 1/9

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integral from-infinity to 0 of e^{9x}

\int_{- \infty}^{0} e^{9 x} d x

\frac{1}{9}

Decimal

0.11111 \dots

Solution steps

\int_{- \infty}^{0} e^{9 x} d x

Compute the indefinite integral:

\int e^{9 x} d x = \frac{1}{9} e^{9 x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{9 x} d x = \frac{1}{9} - 0

= \frac{1}{9} - 0

Simplify

= \frac{1}{9}

t^{2} (\frac{d y}{d t}) + 4 t y - y^{3} = 0

x^{3} + y^{3} - 6 x y = 0, (\frac{4}{3}, \frac{8}{3})

\int_{2}^{5} 4 x^{3} d x

f (x) = \frac{1 - x ^{2}}{( 1 + x ^{2} ) ^{2}}

x \to c lim (327)

What is the integral from-infinity to 0 of e^{9x} ?
The integral from-infinity to 0 of e^{9x} is 1/9