What is the solution for y^'=((x^2e^{y/x}+y^2))/(xy) ?

The solution for y^'=((x^2e^{y/x}+y^2))/(xy) is y=-\W((ln(x)+c_{1})/e)x-x

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y^'=((x^2e^{y/x}+y^2))/(xy)

y^{^{'}} = \frac{( x ^{2} e ^{\frac{y}{x}} + y ^{2} )}{x y}

y = - W (\frac{ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{( x ^{2} e ^{\frac{y}{x}} + y ^{2} )}{x y}

Solve using substitution:

y = - W (\frac{ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{ln ( x ) + c _{1}}{e}) x - x

\frac{\partial}{\partial x} (2 x y + sin (x))

\frac{( e ^{- s} )}{s ( s + 1 )}

\frac{d}{d x} (128 sin (2 x))

y = (x^{2} + 4)^{2}

x^{2}, 0, - 1, 2

What is the solution for y^'=((x^2e^{y/x}+y^2))/(xy) ?
The solution for y^'=((x^2e^{y/x}+y^2))/(xy) is y=-\W((ln(x)+c_{1})/e)x-x