What is the solution for y^'=-y/(x^2)+1/(x^2y^2) ?

The solution for y^'=-y/(x^2)+1/(x^2y^2) is y=\sqrt[3]{-e^{3/x-c_{1}}+1}

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y^'=-y/(x^2)+1/(x^2y^2)

y^{^{'}} = - \frac{y}{x ^{2}} + \frac{1}{x ^{2} y ^{2}}

y = 3 - e^{\frac{3}{x} - c_{1}} + 1

Solution steps

y^{'} (x) = - \frac{y}{x ^{2}} + \frac{1}{x ^{2} y ^{2}}

Solve separable ODE:

y = 3 - e^{\frac{3}{x} - c_{1}} + 1

y = 3 - e^{\frac{3}{x} - c_{1}} + 1

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What is the solution for y^'=-y/(x^2)+1/(x^2y^2) ?
The solution for y^'=-y/(x^2)+1/(x^2y^2) is y=\sqrt[3]{-e^{3/x-c_{1}}+1}