What is the integral of sin(y)cos(y) ?

The integral of sin(y)cos(y) is (sin^2(y))/2+C

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integral of sin(y)cos(y)

\int sin (y) cos (y) d y

\frac{sin ^{2} ( y )}{2} + C

Solution steps

\int sin (y) cos (y) d y

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (y)

= \frac{sin ^{2} ( y )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( y )}{2} + C

\frac{d y}{d x}, x = e^{y}

\int \frac{5}{4 + 9 t ^{2}} d t

y^{3} - (18 x + 6) + 3 x y^{2} y^{^{'}} = 0

\int \frac{arctan ( x )}{x} d x

\frac{d}{d x} (6 x^{2} e^{- x})

What is the integral of sin(y)cos(y) ?
The integral of sin(y)cos(y) is (sin^2(y))/2+C