What is the solution for (dy)/(dx)=xy+3x+2y+6 ?

The solution for (dy)/(dx)=xy+3x+2y+6 is y=e^{(x^2)/2+2x+c_{1}}-3

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(dy)/(dx)=xy+3x+2y+6

\frac{d y}{d x} = x y + 3 x + 2 y + 6

y = e^{\frac{x ^{2}}{2} + 2 x + c_{1}} - 3

Solution steps

\frac{d y}{d x} = x y + 3 x + 2 y + 6

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + 2 x + c_{1}} - 3

y = e^{\frac{x ^{2}}{2} + 2 x + c_{1}} - 3

(y^{2} + 3 x y) d x - 3 x^{2} d y = 0

1 + s

f (x) = 23 sin (x) + 2 cos (x)

\frac{d}{d x} (cosh (\frac{4 x ^{3}}{x - 2}))

y = ln (ln (x^{32}))

What is the solution for (dy)/(dx)=xy+3x+2y+6 ?
The solution for (dy)/(dx)=xy+3x+2y+6 is y=e^{(x^2)/2+2x+c_{1}}-3