What is the derivative of-cos(4x) ?

The derivative of-cos(4x) is 4sin(4x)

What is the first derivative of-cos(4x) ?

The first derivative of-cos(4x) is 4sin(4x)

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\frac{d}{d x} (- cos (4 x))

4 sin (4 x)

Solution steps

\frac{d}{d x} (- cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - (- sin (4 x) \cdot 4)

Simplify

= 4 sin (4 x)

\frac{\partial}{\partial x} (ln (x^{2} + x))

\frac{\partial}{\partial x} (4 x - 4 - y^{2})

\frac{85 t}{99 t - 85}

x \to 3 lim (x^{2} + 2 x - 1)

v + x \cdot \frac{d v}{d x} = x^{2} - 1 + 2 v

What is the derivative of-cos(4x) ?
The derivative of-cos(4x) is 4sin(4x)
What is the first derivative of-cos(4x) ?
The first derivative of-cos(4x) is 4sin(4x)