What is the tangent of f(x)=7x-4x^2,(-3,-57) ?

The tangent of f(x)=7x-4x^2,(-3,-57) is y=31x+36

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=7x-4x^2,(-3,-57)

tangent of

f (x) = 7 x - 4 x^{2}, (- 3, - 57)

y = 31 x + 36

Solution steps

Find the slope of

f (x) = 7 x - 4 x^{2} : \frac{df ( x )}{d x} = 7 - 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 31

Find the line with slope m=

31

and passing through

(- 3, - 57) : y = 31 x + 36

y = 31 x + 36

\frac{d}{d x} (e^{x} (2 x^{4} - 1))

\frac{d ^{2}}{d x ^{2}} (2 x)

\int x \cdot ln (x) d x

\int_{- 4}^{0} (1 + 16 - x^{2}) d x

\int t^{2} 13 t - 1 d t

What is the tangent of f(x)=7x-4x^2,(-3,-57) ?
The tangent of f(x)=7x-4x^2,(-3,-57) is y=31x+36