What is the derivative of x^3-(x^2)/(40) ?

The derivative of x^3-(x^2)/(40) is 3x^2-x/(20)

What is the first derivative of x^3-(x^2)/(40) ?

The first derivative of x^3-(x^2)/(40) is 3x^2-x/(20)

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derivative of

x^{3} - \frac{x ^{2}}{40}

3 x^{2} - \frac{x}{20}

Solution steps

\frac{d}{d x} (x^{3} - \frac{x ^{2}}{40})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (\frac{x ^{2}}{40})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (\frac{x ^{2}}{40}) = \frac{x}{20}

= 3 x^{2} - \frac{x}{20}

y^{^{'}} = 4 + 2 sin (\frac{x}{4}) - \frac{y}{100}

\int \frac{1}{n ( ln ( n ) ) ^{2}}

\int_{0}^{1} (3 - 4 x) e^{2 x} d x

y^{^{''}} + \frac{200}{8} \cdot y = 30 sin (2 x), y (0) = 2, y^{^{'}} (0) = 0

\frac{d}{d x} (- \frac{c}{x ^{2}})

What is the derivative of x^3-(x^2)/(40) ?
The derivative of x^3-(x^2)/(40) is 3x^2-x/(20)
What is the first derivative of x^3-(x^2)/(40) ?
The first derivative of x^3-(x^2)/(40) is 3x^2-x/(20)