What is laplacetransform 2(t-2) ?

The answer to laplacetransform 2(t-2) is 2/(s^2)-4/s

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laplacetransform 2(t-2)

laplace transform

2 (t - 2)

\frac{2}{s ^{2}} - \frac{4}{s}

Solution steps

L {2 (t - 2)}

Expand

2 (t - 2) : 2 t - 4

= L {2 t - 4}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 2 L {t} - L {4}

L {t} : \frac{1}{s ^{2}}

L {4} : \frac{4}{s}

= 2 \cdot \frac{1}{s ^{2}} - \frac{4}{s}

Refine

2 \frac{1}{s ^{2}} - \frac{4}{s} : \frac{2}{s ^{2}} - \frac{4}{s}

= \frac{2}{s ^{2}} - \frac{4}{s}

\int \frac{1}{16 x ^{2} - 24 x - 27} d x

\frac{x}{5}

y = 7 cos (x)

\int t^{2} \cdot ln^{2} (t) d t

x \to 0 lim (x^{- 3})

What is laplacetransform 2(t-2) ?
The answer to laplacetransform 2(t-2) is 2/(s^2)-4/s