What is the derivative of (x^2-9/(x+3)) ?

The derivative of (x^2-9/(x+3)) is 1

What is the first derivative of (x^2-9/(x+3)) ?

The first derivative of (x^2-9/(x+3)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 9}{x + 3})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 9}{x + 3})

Simplify

\frac{x ^{2} - 9}{x + 3} : x - 3

= \frac{d}{d x} (x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (3)

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 1 - 0

Simplify

= 1

7 x \cdot sin (x) + x^{2} \cdot e^{x}

\frac{d}{d x} (\frac{1}{3 x ^{2}} - \frac{5}{2 x})

x^{2} y^{^{'}} - 4 x y = sin (2 x) x^{6}

\frac{d}{d x} (a + b x)

\frac{d}{d x} (\frac{2 x e ^{x}}{x ^{2} + 1})

What is the derivative of (x^2-9/(x+3)) ?
The derivative of (x^2-9/(x+3)) is 1
What is the first derivative of (x^2-9/(x+3)) ?
The first derivative of (x^2-9/(x+3)) is 1