What is the solution for y^{''}+4y^'-45y=0 ?

The solution for y^{''}+4y^'-45y=0 is y=c_{1}e^{5t}+c_{2}e^{-9t}

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y^{''}+4y^'-45y=0

y^{^{''}} + 4 y^{^{'}} - 45 y = 0

y = c_{1} e^{5 t} + c_{2} e^{- 9 t}

Solution steps

y^{''} (t) + 4 y^{'} (t) - 45 y = 0

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} e^{- 9 t}

y = c_{1} e^{5 t} + c_{2} e^{- 9 t}

f (x) = 3.6 x + 500

\int \frac{1}{2 - e ^{3 x}} d x

\frac{d}{d x} ((x + 1) (x - 2)^{2})

n = 1 \sum \infty \frac{3}{n ^{2} + 5 n + 4}

x \to - 4 + lim (\frac{x + 5}{x + 4})

What is the solution for y^{''}+4y^'-45y=0 ?
The solution for y^{''}+4y^'-45y=0 is y=c_{1}e^{5t}+c_{2}e^{-9t}