What is area 2x^3-x^2-5x,-x^2+3x,0,2 ?

The answer to area 2x^3-x^2-5x,-x^2+3x,0,2 is 8

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area 2x^3-x^2-5x,-x^2+3x,0,2

area

2 x^{3} - x^{2} - 5 x, - x^{2} + 3 x, 0, 2

8

Solution steps

Apply the area formula:

\int_{0}^{2} 2 x^{3} - x^{2} - 5 x - (- x^{2} + 3 x) d x

Solve

\int_{0}^{2} 2 x^{3} - x^{2} - 5 x - (- x^{2} + 3 x) d x : 8

The area is:

= 8

\frac{d y}{d x} = \frac{1}{4 - x ^{2}}, y (0) = π

\int 5 tan^{3} (x) sec (x) d x

y^{^{'}} = (1 + t) \cdot y, y (0) = 1

\int \frac{1}{sec ( x )} d x

\frac{d}{d x} ((x^{2} + 1) (x^{3} + x^{2} + 1))

What is area 2x^3-x^2-5x,-x^2+3x,0,2 ?
The answer to area 2x^3-x^2-5x,-x^2+3x,0,2 is 8