What is the integral from 1 to 2 of 1/(x^5) ?

The integral from 1 to 2 of 1/(x^5) is 15/64

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integral from 1 to 2 of 1/(x^5)

\int_{1}^{2} \frac{1}{x ^{5}} d x

\frac{15}{64}

Decimal

0.234375

Solution steps

\int_{1}^{2} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{1}^{2}

= [- \frac{1}{4 x ^{4}}]_{1}^{2}

Compute the boundaries:

\frac{15}{64}

= \frac{15}{64}

\frac{\partial}{\partial x} (y e^{4 x})

\int_{1}^{5} \frac{ln ( x )}{x ^{7}} d x

\frac{d}{d x} (\frac{3}{2} x^{\frac{5}{3}} - \frac{5 x}{4} + 7 x^{2} - \frac{6}{x ^{5}} + 6)

y = (3 x - 2 x^{2})^{3} \frac{d y}{d x}

\frac{d y}{d x} = x^{7} e^{x^{8}}

What is the integral from 1 to 2 of 1/(x^5) ?
The integral from 1 to 2 of 1/(x^5) is 15/64