What is the limit as x approaches-1 of 1/(x^2-2x-3) ?

The limit as x approaches-1 of 1/(x^2-2x-3) is diverges

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limit as x approaches-1 of 1/(x^2-2x-3)

x \to - 1 lim (\frac{1}{x ^{2} - 2 x - 3})

diverges

Solution steps

x \to - 1 lim (\frac{1}{x ^{2} - 2 x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{1}{x ^{2} - 2 x - 3}) = - \infty

x \to - 1 - lim (\frac{1}{x ^{2} - 2 x - 3}) = \infty

= diverges

\frac{\partial}{\partial y} (\frac{x}{y ^{2} + 1})

\frac{\partial}{\partial x} (x^{3} + 4 x^{2} y + 4 x + 2)

x \to 2 - lim (\frac{2}{2 - x})

x \to 0 lim (2 - x^{2})

(1 + w) w^{3} + 9

What is the limit as x approaches-1 of 1/(x^2-2x-3) ?
The limit as x approaches-1 of 1/(x^2-2x-3) is diverges