en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f^'(t)-f(t)=-4t

Solution

f^{^{'}} (t) - f (t) = - 4 t

Solution

f (t) = 4 (t + 1) + c_{1} e^{t}

Solution steps

f^{'} (t) - f (t) = - 4 t

Solve linear ODE:

f (t) = 4 (t + 1) + c_{1} e^{t}

f (t) = 4 (t + 1) + c_{1} e^{t}

Popular Examples

integral from-8 to 1 of 1/(x^{1/3)}

\int_{- 8}^{1} \frac{1}{x ^{\frac{1}{3}}} d x

y^'+8(tan(8x))y=-2cos(8x)

y^{^{'}} + 8 (tan (8 x)) y = - 2 cos (8 x)

derivative of ((t^6))/((t^3+1)^2)derivative of

\frac{( t ^{6} )}{( t ^{3} + 1 ) ^{2}}

integral of (1-sin(θ))^2

\int (1 - sin (θ))^{2} d θ

integral of cos(-1(x))

\int cos (- 1 (x)) d x

Frequently Asked Questions (FAQ)

What is the solution for f^'(t)-f(t)=-4t ?
The solution for f^'(t)-f(t)=-4t is f(t)=4(t+1)+c_{1}e^t