What is (\partial)/(\partial x)(2xy-x^2y) ?

The answer to (\partial)/(\partial x)(2xy-x^2y) is 2y-2yx

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(\partial)/(\partial x)(2xy-x^2y)

\frac{\partial}{\partial x} (2 x y - x^{2} y)

2 y - 2 y x

Solution steps

\frac{\partial}{\partial x} (2 x y - x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (x^{2} y)

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

= 2 y - 2 y x

\int 32 x^{3} - 15 x^{2} + 10 x d x

x + \frac{1}{y} = 2

\int \frac{2 x - 3}{( x - 1 ) ^{2}} d x

x^{2} - 6, x

\int (x^{3} + x)^{9} d x

What is (\partial)/(\partial x)(2xy-x^2y) ?
The answer to (\partial)/(\partial x)(2xy-x^2y) is 2y-2yx