What is (\partial)/(\partial x)(-2x^2+4y^2+3z^2+43) ?

The answer to (\partial)/(\partial x)(-2x^2+4y^2+3z^2+43) is -4x

Popular >

(\partial)/(\partial x)(-2x^2+4y^2+3z^2+43)

\frac{\partial}{\partial x} (- 2 x^{2} + 4 y^{2} + 3 z^{2} + 43)

- 4 x

Solution steps

\frac{\partial}{\partial x} (- 2 x^{2} + 4 y^{2} + 3 z^{2} + 43)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (4 y^{2}) + \frac{\partial}{\partial x} (3 z^{2}) + \frac{\partial}{\partial x} (43)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (4 y^{2}) = 0

\frac{\partial}{\partial x} (3 z^{2}) = 0

\frac{\partial}{\partial x} (43) = 0

= - 4 x + 0 + 0 + 0

Simplify

= - 4 x

\frac{\partial}{\partial y} (2 x + y e^{x})

\frac{d}{d x} (- 4 x^{3} + 10 x^{2} - x)

\frac{\partial}{\partial x} (\frac{2 x}{3 y})

\int arctan (x) x d x

x \to 3 - lim (7 - x)

What is (\partial)/(\partial x)(-2x^2+4y^2+3z^2+43) ?
The answer to (\partial)/(\partial x)(-2x^2+4y^2+3z^2+43) is -4x