What is the d/(dt)(\sqrt[8]{t}-8e^t) ?

The d/(dt)(\sqrt[8]{t}-8e^t) is 1/(8t^{7/8)}-8e^t

What is the first d/(dt)(\sqrt[8]{t}-8e^t) ?

The first d/(dt)(\sqrt[8]{t}-8e^t) is 1/(8t^{7/8)}-8e^t

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\frac{1}{8 t ^{\frac{7}{8}}} - 8 e^{t}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (8 e^{t}) = 8 e^{t}

= \frac{1}{8 t ^{\frac{7}{8}}} - 8 e^{t}

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What is the d/(dt)(\sqrt[8]{t}-8e^t) ?
The d/(dt)(\sqrt[8]{t}-8e^t) is 1/(8t^{7/8)}-8e^t
What is the first d/(dt)(\sqrt[8]{t}-8e^t) ?
The first d/(dt)(\sqrt[8]{t}-8e^t) is 1/(8t^{7/8)}-8e^t