What is the solution for (1+x)y^'+y=sqrt(x) ?

The solution for (1+x)y^'+y=sqrt(x) is y=(2x^{3/2})/(3(1+x))+(c_{1})/(1+x)

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(1+x)y^'+y=sqrt(x)

(1 + x) y^{^{'}} + y = x

y = \frac{2 x ^{\frac{3}{2}}}{3 ( 1 + x )} + \frac{c _{1}}{1 + x}

Solution steps

(1 + x) y^{'} (x) + y = x

Solve linear ODE:

y = \frac{2 x ^{\frac{3}{2}}}{3 ( 1 + x )} + \frac{c _{1}}{1 + x}

y = \frac{2 x ^{\frac{3}{2}}}{3 ( 1 + x )} + \frac{c _{1}}{1 + x}

\frac{\partial}{\partial x} (x^{2} sin (\frac{x}{y}))

\int_{0}^{1} 16 \frac{1}{x ^{p}} d x

x - x^{3} (1)

\int 7 arctan (x) d x

f (x) = \frac{1}{x} + 200

What is the solution for (1+x)y^'+y=sqrt(x) ?
The solution for (1+x)y^'+y=sqrt(x) is y=(2x^{3/2})/(3(1+x))+(c_{1})/(1+x)