What is the integral of ((cot^2(x))/(cos^2(x))) ?

The integral of ((cot^2(x))/(cos^2(x))) is -cot(x)+C

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integral of ((cot^2(x))/(cos^2(x)))

\int (\frac{cot ^{2} ( x )}{cos ^{2} ( x )}) d x

- cot (x) + C

Solution steps

\int \frac{cot ^{2} ( x )}{cos ^{2} ( x )} d x

Simplify

\frac{cot ^{2} ( x )}{cos ^{2} ( x )} : csc^{2} (x)

= \int csc^{2} (x) d x

Use the common integral:

\int csc^{2} (x) d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

\frac{( \frac{10}{6} )}{s ( s ^{2} + \frac{1}{2} )}

\frac{5}{6 x ^{5}}

\int (- 3 x^{4} - 6 x^{2} + 8) d x

2 x \frac{d y}{d x} + 2 y = x^{3} y^{4}

\int 18 y^{2} d y

What is the integral of ((cot^2(x))/(cos^2(x))) ?
The integral of ((cot^2(x))/(cos^2(x))) is -cot(x)+C