What is the derivative of (x^2/6-x) ?

The derivative of (x^2/6-x) is x/3-1

What is the first derivative of (x^2/6-x) ?

The first derivative of (x^2/6-x) is x/3-1

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\frac{d}{d x} (\frac{x ^{2}}{6} - x)

\frac{x}{3} - 1

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{6} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{6}) - \frac{d x}{d x}

\frac{d}{d x} (\frac{x ^{2}}{6}) = \frac{x}{3}

\frac{d x}{d x} = 1

= \frac{x}{3} - 1

\frac{\partial}{\partial x} (sin (\frac{3 x}{y}))

\frac{d}{d x} (e^{(x^{2})})

\int \frac{x + 4}{x ^{2} + 8 x} d x

x y^{^{'}} + y = 2 x

x \to - \infty lim (x e^{x})

What is the derivative of (x^2/6-x) ?
The derivative of (x^2/6-x) is x/3-1
What is the first derivative of (x^2/6-x) ?
The first derivative of (x^2/6-x) is x/3-1